oxidation number of S in H2SO5
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H2SO5 has an oxygen-oxygen bond. This means that two of the five oxygen atoms have a formal charge of −1−1. Same case as in H2O2HX2OX2.
2⋅(+1)+1⋅(x)+3⋅(−2)+2⋅(−1)=02+x−6−2=0x=+62⋅(+1)+1⋅(x)+3⋅(−2)+2⋅(−1)=02+x−6−2=0x=+6
You have 3 oxygens with formal charge −2−2 and 2 oxygen atoms with −1−1.
2⋅(+1)+1⋅(x)+3⋅(−2)+2⋅(−1)=02+x−6−2=0x=+62⋅(+1)+1⋅(x)+3⋅(−2)+2⋅(−1)=02+x−6−2=0x=+6
You have 3 oxygens with formal charge −2−2 and 2 oxygen atoms with −1−1.
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