Question

Oxidation number of S in Na₂ SO₄ is
(a) – 2 (b) + 2
(c) – 6 (d) + 6

Answer 1

Explanation:

let it be x

(+1)2+x+(-2)4=0

x=+6

Answer 2

(d) + 6

Explanation:

Oxidation number of S in Na2SO4 can be calculated as follows:

2(+1) + + x -2(4) = 0 where oxidation number of Sodium is +1, and oxygen is -2.

2 + x -8 = 0

x -6 = 0

Therefore x = +6

Option D is the answer.