Chemistry, asked by harsh77777, 11 months ago

Oxidation number of S in so4_2
(Bihar MEE 19
(a) + 6
(b) +3
(c) + 2N
(d) - 2

Answers

Answered by athulliagiri

0

Answer:+6

Explanation:For SO4^2- ,

So, x-(-4×2)=-2

ie, x-8=-2

Finally, X=6; ie, S=6

Answered by hritikVK18

0

The Oxidation Number Of Sulphur Will Be +6

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