oxidation Number of So3–2
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2
Answer:
Explanation: The oxidation state of the sulfur is +6 (work it out!); therefore, the ion is more properly named the sulfate(VI) ion. The sulfite ion is SO32-. The oxidation state of the sulfur is +4.
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Answer:
oxidation number of S in SO3-2 is +4
Explanation:
let oxidation number of S be x
oxidation number of O is -2
so, x+3(-2)= -2
x-6=-2
x= +4
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