Question

Oxidation number of SO4 in AL2(SO4)3​

Answer 1

Answer:

In case of  Al2(SO4)3:

Consider just the sulfate ion: SO4^2-

Oxidation # of S + 4( oxidation number of O) = -2

Oxidation # of S + 4(-2) = -2

Oxidation # of S = +6

If you wanted to do the same thing for Al2(SO4)3:

2(ox # Al) + 3(ox # S) + 12(ox # O) = 0

2(+3) + 3(S) + 12(-2) = 0

3S = +18

S = +6

In case of Na2S2O3:

+1 for Na = 2x+1 = +2

-2 for O = 3x-2= -6

We know Total cargo stable molecule (non-charged) = 0

+2 -6 + 2S =0

2S = +4

S=+2

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Explanation:

Answer 2

Explanation:

S is +6. That last line Damon is showing that it checks out for S = +6 combined with -8 for the 4 O atoms leaves -2 for the SO4 ion as it should be