oxidation number of sulphur in H2S
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Answered by
2
Let oxidation number be x
So
2 + x =0
x = -2
So
2 + x =0
x = -2
Answered by
0
Hi there!!
The Oxidation number of S in H2S is:
H2S => 2 (1) + 1(X) = 0
=> 2 + X = 0
Therefore, X = -2.
The sum of the oxidation numbers in a compound must equal zero.
In the compound hydrogen sulphide, H2S, the two hydrogen atoms have an oxidation number of +1, for a total of +2.
Therefore, the oxidation number of sulphur in the compound is -2, and the sum of the oxidation numbers is 0.
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The Oxidation number of S in H2S is:
H2S => 2 (1) + 1(X) = 0
=> 2 + X = 0
Therefore, X = -2.
The sum of the oxidation numbers in a compound must equal zero.
In the compound hydrogen sulphide, H2S, the two hydrogen atoms have an oxidation number of +1, for a total of +2.
Therefore, the oxidation number of sulphur in the compound is -2, and the sum of the oxidation numbers is 0.
Mark me as brainliest if u like it....plzzz.....
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