oxidation number of sulphur in K2S2O8
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let oxidation no of sulphur be x
oxidation no of potassium is +1
oxidation no of oxygen is -2
so 2+2x-16=0
-14+2x=0
2x=14
x=14/2
x=7
oxidation no of potassium is +1
oxidation no of oxygen is -2
so 2+2x-16=0
-14+2x=0
2x=14
x=14/2
x=7
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