Chemistry, asked by vinalganglani, 10 months ago

oxidation number of sulphur in [SO3]*-2​

Answers

Answered by sreshtaa20059
1

Given,[SO3]^-2,

let sulphur be x,

=>x+(-2)3=-2

=>x+(-6)=-2

=>x-6=-2

=>x=-2+6

=>x=4

Therefore,oxidation number of sulphur is +4

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