Question

Oxidation number of V in Cs4Na(HV10O28)

Answer 1

Answer:

THE ANSWER IS +5

Explanation:

PLEASE MARK AS BRAINLIST ANSWER

Answer 2

Answer:

The oxidation number is $+5$.

Explanation:

Let the oxidation state of V be $x$ in $Cs_{4} Na(HV_{10} O_{28} )$.

$H(1)+1+1+10x-2(28)=0$

$6+10x-56=0$

$10x=50$

$x=+5$

Oxidation number : The total number of electrons that an atom acquires or loses in order to create a chemical connection with another atom is known as the oxidation number. It is also known as the oxidation state.