Question

Oxidation numbers of H4p2o7

Answer 1

Let the oxidation number of p be x

oxidation number of H = 1

Oxidation number of O = -2

It's neither a cation nor anion

So, the equation for this will be,

1 *4 + 2* x + (-2) 7 = 0

4 + 2x - 14 = 0

2x - 10 = 0

2x = 10

x = 5

Answer 2

H. +1

P. +5

O. -2

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