Question

Oxidation numbers of P in PO₄³⁻ , of S in SO₄²⁻ and that of Cr
in Cr₂ O₇²⁻ are respectively [2009]
(a) + 3, + 6 and + 5 (b) + 5, + 3 and + 6
(c) – 3, + 6 and + 6 (d) + 5, + 6 and + 6

Answer 1

Answer:

option d correct

i)P+4(-2)= -3

P= +5

ii)S+4(-2) = -2

S= +6

iii) 2(cr)+7(-2)= -2

cr = +6

Answer 2

Oxidation numbers of P in PO₄³⁻ , of S in SO₄²⁻ and that of Cr

in Cr₂ O₇²⁻ are + 5, + 6 and + 6

Explanation:

Oxidation number

• It is the chemical reaction, which loss electrons.
• The oxidation number will raise during this reaction.
• It may be positive, zero or negative.
• Antoine Lavoisier was first studied the oxidation.
• The oxidation number of oxygen is -2.

Given PO₄³⁻,

P+4(-2) = -3

P+8 = -3

P = +5.

Given SO₄²,

S+4(-2) = -2

S+8 = -2

S= +6 .

Given Cr₂ O₇²⁻,

2(Cr) +7(-2) = -2

2(Cr) +14 = -2

2(Cr) = 12

Cr = +6 .

To learn more;

1. https://brainly.in/question/2161394
2. https://brainly.in/question/11984356