Question

Oxidation numbers should be used to answer this question.
A redox reaction takes place between hydroxylammonium ions, [NH3OH]+, and acidified iron(III)
ions, Fe3+. The products are iron(II) ions, Fe2+, H+ ions, water and a compound of nitrogen.
The mole ratio of reacting hydroxylammonium ions to reacting iron(III) ions is 1 : 2.
Which nitrogen-containing compound could be formed in the reaction?
A) NH3 B) N2O C) NO D) NO2
Answer is B, BUT WHY?

Answer 1

Answer is B becausewhenthere hydrogen rects to forms hydro oxide lammonium

Answer 2

Option B) N2O is the answer:

The answer is N2O because:

• In the reaction we are trying to find the missing component:
• [NH3OH]+   +   H+   +  $FE^{3+}$ →  FE2+   + H+   + H2O  + ?

• This can be found by solving NH3OH separately.
• from [NH3]2+ and  [OH]- the answer is +1 so the charge of one hydrogen will be +1 so the 3 hydrogens will have a charge of 3 and the nitrogen will have a charge of -1 and for OH- hydrogen has a charge of +1 and oxygen has a charge of 2-
• Therefore the new balanced equation will be:
• [NH3OH]+   +   H+   + 2 $FE^{3+}$ → 2 FE2+   + H+   + H2O  + ?'
• to complete the equation there is a need for nitrogen and oxygen and therefore N2O is the answer.

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