Oxidation of 0.2 g of organic compound which contains
Cand H, produced 0.58 g of CO2 and 0.123 g of H,O when
the remainder being oxygen.
Calculate the percentage of Cand H in the organic
compound
Answers
Answer:
73.34 %
Explanation:
Correct option is
D
C=20 %, H=6.66 %, O=73.34 %
Weight of organic compound = 0.2g
Weight of CO
2
= 0.15g
Weight of H
2
O = 0.12g
Molecular weight of CO
2
= 44
Molecular weight of H
2
O = 18
Atomic weight of carbon = 12u
Atomic weight of H
2
= 2u
Percentage of carbon=
Molecular weight of CO
2
Atomic weight of carbon
×
Weightoforganiccompound
Weight of CO
2
×100
Percentage of carbon=
44
12
×
0.2
0.15
×100=20.45%≈20%
Percentage of Hydrogen=
Molecular weight of H
2
O
Atomic weight of Hydrogen
×
Weightoforganiccompound
Weight of H
2
O
×100
Percentage of Hydrogen=
18
2
×
0.2
0.12
×100=6.66%
Percentage of oxygen = 100 - (Percentage of carbon + Percentage of hydrogen) = 100 - (20 + 6.66) = 100 - 26.66 = 73.34 %
HOPE IT HELP's
It took me time to make this all so please
MARK AS BRAINLIEST