oxidation satate of s in HSo4
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Answered by
1
it is very simple to identify oxidation state
H2SO4
S-6
HSO4
oxidation state of Honor is 1
and
O oxidation state is -2
let oxidation state of sulphur is # then.
1 (1)+#+4 (-2)
1+#+(-8)
-7.
I think this compound exist please check your question
H2SO4
S-6
HSO4
oxidation state of Honor is 1
and
O oxidation state is -2
let oxidation state of sulphur is # then.
1 (1)+#+4 (-2)
1+#+(-8)
-7.
I think this compound exist please check your question
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manishp1:
it was not H2so4 it was HSo4
Answered by
1
Oxidation number of Hydrogen is +1
Oxidation number of Oxygen is -2.
(i) Oxidation number of sulphur in H2S.
Let the oxidation number of S be x.
2 (+1) + x = 0
x = -2
Hence, the oxidation number of S in H2S = -2
(ii) Oxidation state of S in H2SO4
Let the oxidation state of S be X
2 (+1) + X + 4(-2) = 0
X = +6
Hence, the oxidation state of Sulphur in H2SO4 is +6.
hope its helps
Oxidation number of Oxygen is -2.
(i) Oxidation number of sulphur in H2S.
Let the oxidation number of S be x.
2 (+1) + x = 0
x = -2
Hence, the oxidation number of S in H2S = -2
(ii) Oxidation state of S in H2SO4
Let the oxidation state of S be X
2 (+1) + X + 4(-2) = 0
X = +6
Hence, the oxidation state of Sulphur in H2SO4 is +6.
hope its helps
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