Oxidation state of B in NaBH4 is
Answers
Answered by
0
Answer:
-5
Explanation:
+1+x+4(+1)=0
x+5=0
x=-5
Answered by
1
Answer:
+3
As the oxidation state of Na is +1 and Hydrogen is -1 because here hydrogen exist as hydride. Hence the oxidation state of boron is +3
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