Oxidation state of (BF4)-1
Answers
Answered by
3
Answer:
+3
Explanation:
X+4(-1)= -1
X = -1+4
X= 3
Answered by
0
Answer:
Boron is in +3 oxidation state.
Explanation:
Here, in [BF4]^-1
we know that Fluorine being the most electronegative element, its oxidation number will be always -1 , there for,
let x be the oxidation number of Boron and oxidation number of Fluorine is -1
thus,
x+(-1x4)=-1
x-4=-1
x=+3
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