Oxidation state of C in C6H12O7
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Answer:
C6H12O6
6x+12−12=0
C has oxidation number =0
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Answer:
let the oxidation number of C is x
so oxidation number of C6=6x
oxidation number of H12=12×1=12
oxidation number of O7=7×(-2)= -14
then the oxidation number of C6H12O6=0
that means 6x+12-14=0
6x-2=0
6x=2
x=2/6=1/3
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