Question

oxidation state of carbon in Na2C2 is? A) -1 B) -2 c) -4

Answer 1

Hi friend,
Given compound,Na2C2

We know the Oxidation state of Na is '+1' as it belongs to I A group.

Na2C2

2(Na)+2(C)=0
2(+1)+2(C)=0
2+2C=0
2C= -2
C= -2/2
C= -1

Oxidation state of Carbon in given compound is “-1”.

hope it helps

Answer 2

Option A)  is correct i.e -1

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Oxidation state of carbon in Na2C2 is "-1".

Reason -Given compound is 

Na2C2

2(Na)+2(C)=0
2(+1)+2(C)=0          (We know that oxidation state of Na is +1)
2  +  2C=0
2C =    -2
C   =   -2/2
⇒C= -1

Hope it will help u ..
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Best of luck ;)
ROYALJATT