Question

oxidation state of cr in cr(h2o)6^3+​

Answer 1

HERE IS YOUR ANSWER. . .

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Cr(H2O)6 3+: s = +3 (The sum of the oxidation states on the ion is equal to the charge. Each water molecule has zero oxidation state overall because they are neutral molecules. So the only contribution to the +3 charge is the oxidation state of the chromium.)

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Answer 2

Answer:

The oxidation state of Cr in Cr(H₂O)₆³⁺ is +3.

Let's recall some of the rules for calculating oxidation states.

• The oxidation state of O is almost always -2.

• The oxidation state of H is almost always +1.

• The sum of all the oxidation states equals the charge on the ion.

If H = +1, then 2H = +2. If O = -2, then 2H + O = +2 - 2 = 0.

Thus, the H₂O units do not contribute to the charge on the ion. The only atom that contributes is the Cr atom.

Since the charge on the ion is 3+, the oxidation state of Cr is +3.