Question

Oxidation state of cr in [cr(nh3)6]so4

Answer 1

Answer:

2

Explanation:

let the oxidation no. of Cr be x.

then,

x+6[(-3)+3(1)]+6+4(-2)=0

x+6[-3+3]+6-8=0

x+6[0]-2=0

x+0-2=0

x-2=0

x=2

Answer 2

Oxidation state of Cr in [Cr(NH₃)6]SO₄ is +2.

Explanation:

A coordination complex consists of a central metal atom or ion bonded to ligands by coordinate covalent bonds. The ligands and the central metal together form the coordination sphere.

[Cr(NH₃)6]SO₄

Central metal atom : Cr

Coordination sphere consists of  6 NH₃ neutral ligands and as sulphate carries a 2- charge ,the coordination sphere carries a +2 charge as the the coordination compound is electrically neutral.

Let the oxidation state of Co = x

Oxidation state of NH₃ ligand = 0    

∴ x + (0) × 6 = +2

x = +2

Oxidation state of Cr = +2

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