oxidation state of cu(no3)2
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⏩The first step is jot down the charges of the elements since it is an ionic bond. Cu=+2, N=+5, O=-2.
⏩Simply add the numbers based on the formula:
▶️0= +2 (2(+5) + 2×3(-2))
▶️0= +2 (+ 10 - 12)
▶️0=0
⏺️Therefore , The above maths clearly proves that the charges of the elements in the ionic bond is equal to Cu=+2, N=+5, O=-2 Hence, it is the oxidation number.
⏩Simply add the numbers based on the formula:
▶️0= +2 (2(+5) + 2×3(-2))
▶️0= +2 (+ 10 - 12)
▶️0=0
⏺️Therefore , The above maths clearly proves that the charges of the elements in the ionic bond is equal to Cu=+2, N=+5, O=-2 Hence, it is the oxidation number.
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