oxidation state of Fe in K₄[Fe(CN)₆] is what
Anonymous:
do u have test tomorrow we also are in same topic right now great na
r u in 12
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oxidation no of CN
C=+2
N= -3
CN = +2-3 = -1
Total oxidation = 0
4(K) + Fe + 6 (CN) = 0
4(+1) + Fe + 6(-1) = 0
4 + Fe - 6 = 0
Fe - 2 = 0
Fe = +2
C=+2
N= -3
CN = +2-3 = -1
Total oxidation = 0
4(K) + Fe + 6 (CN) = 0
4(+1) + Fe + 6(-1) = 0
4 + Fe - 6 = 0
Fe - 2 = 0
Fe = +2
ya done
but carbon is -4 na
not in all case
oxidation of carbon is not stationary
how to know in which case what it is
???? how can u prove it is +2 here
the position of hydrogen determines the o.no of carbon in cn'
ok
very nice
thnkx
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