Chemistry, asked by sanikakale362, 15 hours ago

oxidation state of given compound​

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Answered by rlakshmisha2004
0

Explanation:

a) -2

b)+1

c)0 neutral

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Answered by antramahi2007
0

The oxidation number of the sulfur atom in the SO42- ion must be +6, for example, because the sum of the oxidation numbers of the atoms in this ion must equal -2.

For NH4+, the oxidation number of hydrogen is +1. Therefore, the oxidation number of Nitrogen in Ammonium ion is -3.

It is +5 .

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