oxidation state of given compound
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Explanation:
a) -2
b)+1
c)0 neutral
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The oxidation number of the sulfur atom in the SO42- ion must be +6, for example, because the sum of the oxidation numbers of the atoms in this ion must equal -2.
For NH4+, the oxidation number of hydrogen is +1. Therefore, the oxidation number of Nitrogen in Ammonium ion is -3.
It is +5 .
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