Chemistry, asked by krishnavenigajjala19, 11 months ago

Oxidation state of iron in Fool's gold​

Answers

Answered by binnybhatia25
0

Answer:

Iron pyrites is

iron persulfide

,

F

e

S

2

, with a formal

F

e

(

I

I

+

)

oxidation state.

Explanation:

The sulfur binds as a

persulfide

, i.e.

S

S

; think

peroxide

,

O

2

2

. The formal oxidation state of

S

here is

I

.

Explanation:

Hope it helps

Answered by Anonymous
4

Answer:

Fe2+S2(2−)  = Formula of fool's Gold

Now you can have your answer by calculating oxd. state from this .

Hope it helps .

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