Question

oxidation state of Mn in KMnO4​

Answer 1

$<u> <b> Heya!</b></u>$

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$<u>→›Finding Oxidation number</u>$ ‹←

$<b> =>Given Compound - KMnO4 </b>$

▪Here we know that ,

Oxidation number of :

Potassium k = +1 ,

Oxygen = (4 × -2 ) = -8

✔Let oxidation number of Mn be x

•°• We have

=> x + 1 - 8 = 0

=> x - 7 = 0

=★ x = 7

•°• $<i> The oxidation number of Manganese ( Mn) is +7 </i>$

[ Note ]

=> Oxidation Number is an imaginary charge that appears on an element that appears when it is in combined state with other elements

Thanks !!

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