Oxidation state of na3{co(no2)6}
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In In this In this compound let o. s. Of Co is x
Since Na is alkali metal it's o.S. Is always +1 and NO2 is nitrite ion and it's o.s. is -1
Hence 3×(+1) +x+6 (-1)=0 since total charge on compound is 0
Hence from here x= +3
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