Question

Oxidation state of nitrogen in the explosive formed by reaction of ammonia and iodine

Answer 1

Nitrogen triiodide...

Answer 2

The oxidation state of nitrogen in the explosive formed by the reaction of ammonia and iodine is -3.

Explanation:

• When ammonia reacts with iodine it leads to the formation of an explosive compound called nitrogen triiodide. The chemical equation involved in the reaction is as follows:

$2NH_3+3I_2\rightarrow 2NI_3+3H_2$

• We know that the sum of charges of all atoms present in the compound is equal to zero.
• Let the oxidation state of nitrogen be 'X'. As in the compound, the atom attached with nitrogen is iodine which is a halogen, its oxidation state is +1.

∴ The oxidation state of 'N' in $NI_3$ is

1(X) + 3(1) = 0

X + 3 = 0

X = -3

• From the above calculation it is inferred that the oxidation state of nitrogen in in the explosive $(NI_3)$ formed by reaction of ammonia and iodine is -3.

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