oxidation state of nitrogen is highest in a) n3h b) n2o2 c) nh2oh d) nh3
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Answered by
1
Answer:
(i) N
3
H
O.S.⇒3x+1=0
x=−1/3
(ii) NH
3
O.S.⇒x+3=0
x=−3
(iii)NH
2
−OH
O.S.⇒x+2−1=0
x=−1
(iv) N
2
H
4
O.S.⇒2x+4=0
x=
2
−4
=−2
∴ Highest oxidation state of nitrogen is =−1/3
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