oxidation state of S in H2S2O8
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Answered by
6
H2S2O8
= 2+2x+[-2]*6+[-1]*2
=2x-12
2x-12=0
2x=12
x=12/2
x=6
So oxidation no.of S in H2S2O8 is +6
= 2+2x+[-2]*6+[-1]*2
=2x-12
2x-12=0
2x=12
x=12/2
x=6
So oxidation no.of S in H2S2O8 is +6
jayapradha:
with diagramatic representation please
Answered by
0
+14 is the answer
O is -2
in this case H is +1
so
S=-(8×-2 + 2× +1)
S = +14
O is -2
in this case H is +1
so
S=-(8×-2 + 2× +1)
S = +14
I think 6 is answer
no
how?
diagramatic representation please
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