Question

oxidation state of S in H2S2O8

Answer 1

H2S2O8

= 2+2x+[-2]*6+[-1]*2

=2x-12

2x-12=0

2x=12

x=12/2

x=6

So oxidation no.of S in H2S2O8 is +6

Answer 2

+14 is the answer
O is -2
in this case H is +1
so
S=-(8×-2 + 2× +1)
S = +14