Question

Oxidation state of S in (NH4)2S2O8

Answer 1

Answer:

Oxidation state of sulphur is +7.

Explanation:

Oxidation state is generally a combining capacity of the element.

Let the oxidation state of Sulphur in given molecule is $x$

We know that the oxidation state of ammonium ion $NH_{4}$ IS +1.

We also know the oxidation state of oxygen is -2.

$(NH_{4} )_{2}S_{2}O_{8} }$

$2\times 1+2x-2\times8=0$

$-14+2x=0$

$x = \dfrac{14}{2} = 7$

$x=7$

So, oxidation state of sulphur is +7.

Answer 2

Answer:

HOPE THIS WOULD HELP YOU