Question

Oxidation states of P in H4P205,H4P2O6,H4P2O7, are respectively:

Answer 1

Oxidation state of H is +1.

Oxidation state of O is - 2

Let oxidation state of P be x in each case

In H4P205,

4(+1) + 2x + 5(-2) = 0

4 - 10+ 2x = 0

2x = 6

x = +3.

InH4P2O6

4(+1) + 2x +6(-2) = 0

4 - 12 +2x = 0

2x = 8

x = +4.

In H4P2O7

4(+1) + 2x + 7(-2) = 0

4 - 14 +2x = 0

2x = 10

x = +5.

Answer 2

H₄P₂O₅ = 4 + 2X -10 = 0 => -6 + 2X = 0 => 2X = 6 => X = 3

H₄P₂O₆ = 4 + 2X -12 = 0 => 2X - 8 = 0 => 2X = 8 => X = 4

H₄P₂O₇ = 4 + 2X -14 = 0 => 2X - 10 = 0 => 2X = 10 => X = 5