Question

Oxide ions in cubic close packed arrangement with metal ions occupy two thirds of the octahedral voids .what is the formula of the oxide?

Answer 1

Answer:

i guess this is the answer...

I'm not sure whether this is correct!!!

Answer 2

Answer:-

Oxide ions are arranged in HCP in HCP thre 6 oxide ions per unite cell.

Numbers of octahedral voids= no. of atom per unit cell.

=6

out of 6 octaheadral voids

3

1

are empty.

So, 6×

3

1

= 2 voids are not there

hence 6−2=4 are present

M4O6

M2O3

__________________________________

HOPE THIS WILL HELPS YOU..

Thank you!!