oxidizing agent,reducing agent,substance reduced ,substance oxidised in this reaction
Answers
Answer:
Step-by-step explanation:
on the left hand side of the equation we need to find the oxidation numbers :
always - hydrogen = +1. write +1 above hydrogen. total charge on h2o2 = 0 so that makes oxygen oxidation state = -1 [ 2 hydrogens = +2 , 2 oxygens = -2 cancelled out to give zero ]
do the same process on the RHS. we get oxidation numbers of oxygen as -2 in h20 and 0 in oxygen gas.
remember to ignore the stoichiometric coefficients they do not play a role
oxygen changes from -1 to zero and -2 so h202 is oxidized as well as reduced
this is called a disproportionation reaction
the answers to all the 4 questions is H2O2 only
one molecule reduces the other and the other oxidizes the first one.
that is why we take 2 moles of h2o2
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