Chemistry, asked by ash6180, 8 months ago

Oxygen (0,8) and sulphur (S, 16) belong to group 16 of the periodic table.-
(i) Write the electronic configuration and valence of these two elements?
(ii) Which among these will be more electronegative? Why?​

Answers

Answered by ahitfulmali11
11

valancy of both are -2

hope it's usefull

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Answered by ChitranjanMahajan
23

(i) Electronic configuration of oxygen and sulphur is (2, 6) and (2, 8, 6) respectively, and their valency is -2.

ii) Oxygen is more electronegative than sulphur.

i) The electronic configuration of oxygen is (2, 6) as it has an atomic number of 8. It's valency is -2 because oxygen gains two electrons to complete its octet.

The electronic configuration of sulphur is (2, 8, 6) as it has an atomic number of 16. It's valency is also -2 as it gains two electrons to complete its octet.

(ii) Oxygen is more electronegative than sulphur because oxygen accepts electrons more readily than sulphur.

• Electronegativity is the tendency to accept electrons.

• Oxygen has two shells and sulphur has three shells. Therefore, the nuclear pull on the valence electrons of oxygen is more than that on the valence electrons of sulphur.

• Due to lesser shielding effect and greater nuclear pull, the tendency to accept electrons is more in oxygen than in sulphur.

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