Question

oxygen and nitrogen are present in a mixture in the ratio 1:4 by weight.
calculate the ratio between their molecules.​

Answer 1

Q. oxygen and nitrogen are present in a mixture in the ratio 1:4 by weight.calculate the ratio between their molecules.

Ans:- Ratio of molecules of O2 and N2 = 7:32

Let wt. of given mixture = Wg

$amount \: of \: oxygen \: in \: mixture = \frac{w \times 1}{5} g = \frac{w}{5} g$

$amount \: of \: nitrogen \: in \: mixture = \frac{w \times 4}{5} = \frac{4w}{5} g$

$moles \: of \: oxygen \: = \frac{w}{5 \times 32}$

$molecules \: of \: oxygen \: = \frac{w}{5 \times 32} \times 6.022 \times {10}^{23}$

$moles \: of \: nitrogen \: = \frac{4w}{5 \times 28}$

$molecules \: of \: nitrogen \: = \frac{4w}{5 \times 28} \times 6.022 \times {10}^{23}$

$ratio \: of \: molecules \: of \: oxygen \: and \: nitrogen \: =$

$\frac{w}{5 \times 32} \times 6.022 \times {10}^{23} = \frac{4w}{5 \times 28} \times 6.022 \times {10}^{23}$

$\frac{1}{32} = \frac{1}{7}$

$\frac{7}{32} or \: 7 \: ratio \: 32$

Answer 2

Answer:

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Solution:-

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let weight of mixture =>Wg

Amount of O2 in mixture =>w x1/5* g

Amount of N2 in mixture =>w x 4/5* g

Ratio of moles of oxygen and nitrogen

=>w /5 x 32 * 6.022 x 10^23 =4w/5 x 28* 6.022 x 10^23

=>1/32=1/7

=>Ratio=>7:32

hope helps✊