Question

oxygen atoms in 44g of carbon dioxide (atomic mass:C=12u,O=16u)

Answer 1

No of atoms = moles x avagadro number
no of atoms = given mass/molar mass x 6.022x10^23
= 44/ 12 + 2 x 16 = 44 / 44 = 1 mole 

no of atoms = 1 x 6.022 x 10^23
= 6.022 x$10^{23}$

Answer 2

No of atoms = moles x avagadro number
no of atoms = given mass/molar mass x 6.022x10^23
= 44/ 12 + 2 x 16 = 44 / 44 = 1 mole 

no of atoms = 1 x 6.022 x 10^23
= 6.022 x