oxygen boils at -185°c, this is approximately how much?
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The rate of degrees m = F/C = 180/100 = 1.8 deg F/deg C between freezing and boiling.
So from the straight line general equation we can write F = m C + b = 1.8 C + 32, where F = 32 = b deg F when C = 0 deg C, the two freezing points.
And there, we've just derived the equation for finding F from C. Using the physics. As it should be learned.
Now you just plug and chug the derived equation. When C = - 183 deg, we have F = 1.8*(-183) + 32 = -297.4 deg F, which is the same as the other answer, but now you know why. Now you know the physics.
So from the straight line general equation we can write F = m C + b = 1.8 C + 32, where F = 32 = b deg F when C = 0 deg C, the two freezing points.
And there, we've just derived the equation for finding F from C. Using the physics. As it should be learned.
Now you just plug and chug the derived equation. When C = - 183 deg, we have F = 1.8*(-183) + 32 = -297.4 deg F, which is the same as the other answer, but now you know why. Now you know the physics.
Gladish1111:
thanks u
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