Question

oxygen is produced by catalytic decomposition of KClO3 . 2KClвЗТвЗТ2KCl + 3O2. calculate the amount of KClO3 required to produce 2.4 moles of oxygen

Answer 1

The equation is as follows:          

                              MnO2

         2KCLO3 ------------------> 2KCl  + 3O2

The mole ratio for O2:KCLO3 is 3:2

Therefore 2.4 moles of oxygen requires:

if 3 = 2.4 moles

Then 2= 2.4 x 2/3

           =  0.8 x 2 = 1.6 moles

Moles = mass/molar mass

mass= moles x molar mass

moles= 1.6

molar mass of KClO3= 122.5

Therefore mass = 1.6 x 122.5

                          = 196 g