Oxygen produced by thermal decomposition of 50 g of KCLO3 .
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2KClO₃ = 2KCl + 3O₂
2(38+35.5+48) 3(2×16)
=243 = 96
So from 243g KClO₃ 96g O₂ is produced
so (96/243)×50 g O₂ = 19.75g O₂ is produced from 50g KClO₃
2(38+35.5+48) 3(2×16)
=243 = 96
So from 243g KClO₃ 96g O₂ is produced
so (96/243)×50 g O₂ = 19.75g O₂ is produced from 50g KClO₃
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