Question

p(0,5) and (12,0) find the distance​

Answer 1

Answer:

p(0,5) and Q (12,0)

formula of distance is √(X2-X1)^2 - (Y2-Y1)^2

√(12-0)^2 -(0-5)^2

√144+25=√169

=13

Step-by-step explanation:

Hope it is helpful

Answer 2

Answer:

13

Step-by-step explanation:

Distance between two coordinates = $\sqrt{(x_{2} -x_{1})^2 + (y_{2}-y_{1})^2 }$

Given,

$x_{1} = 0\\ y_{1} = 5\\\\x_{2}= 12\\y_{2}=0$

So distance = $\sqrt{(12-0)^2+(0-5)^2}$

                    = $\sqrt{12^2+(-5)^2}$

                    = $\sqrt{144+25}$

                    = $\sqrt{169}$

                    = 13

Please mark my answer as the brainliest.