Question

P(0),p(1),p(2)forp(y)=y²-3y+1

Answer 1

Step-by-step explanation:

p(y)=y2-3y+1

p(0)=0×0-3(0)+1

p(0)=+1

p(1)=1×1-3(1)+1

=1-3+1

=2-3

p(1) =-1

p(2)=2×2-3(2)+1

=4-6+1

=5-6

p(2)=-1

make me as brainlist