Question

P(1)=1^2-3(1)-4 find the zeroes of the polynomial

Answer 1

Answer:

The zeroes of the given polynomial are -1 and 4.

Step-by-step explanation:

P(x) = x^2 - 3x - 4

Here, x^2 - 3x - 4 = 0

x^2 - (4x - x) - 4 = 0

x^2 - 4x + x - 4 = 0

x(x-4) + 1(x-4) = 0

(x+1)(x-4) = 0

x = -1, 4