Question

P(×)=(×+1) (×-2) ×=-1,2
Zero of polynomial

Answer 1

Answer:

x^2 - x - 2

Step-by-step explanation:

$x = - 1 \: \: \: \: x = 2 \\ x + 1 = 0 \: \: \: \: x - 2 = 0 \\ (x + 1)(x - 2) = 0 \\ {x}^{2} - 2x + x - 2 = 0 \\ {x}^{2} - x - 2 = 0$

hope you get your answer