P={1,2,3,4} , Q={3,4,5,6} , R={4,5,6,7,8} verify n(PUQ) = n(P) - n(Q)-n(P n Q)
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Answered by
4
Answer:
If your question is n(PUQ) = n(P) + n(Q) - n(PnQ)
Step-by-step explanation:
P = {1,2,3,4} → n(P) = 4
Q = {3,4,5,6} → n(Q) = 4
PUQ = {1,2,3,4,5,6} → n(PUQ) = 6
PnQ = {3,4} → n(PnQ) = 2
Substitute the values: RHS is
=> 6
Substitute the values: LHS is
=> 4 + 4 - 2
=> 6
Both are equal, as desired.
Answered by
1
Step-by-step explanation:
n(PUQ)=1,2,3,4,5,6=6
n(P)=4
n(Q)=4
n(PnQ)=2
n(P)-n(Q)-n(PnQ)=4-4-2=-2
so therefore,n(P) not equal to n(P)-n(Q)-n(PnQ)
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