Question

(p+1)^2-(p)^2=17
Find the p value

Answer 1

Step-by-step explanation:

(p+1)²-p²=17

p²+1²+2(p)(1)-p²=17

1+2p=17

2p=17-1

p=16/2

p=8

Answer 2

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❥︎ Given :

$(p + 1)^{2} - p^{2} = 17$

❥︎ To Find :

The value of p

❥︎ Solution :

We know that,

$\fbox {(a + b)² = a² + 2ab + b²}$

➛ By using this identity, we can factorise $(p + 1)^{2}$

⇒ $(p + 1)^{2} - p^{2} = 17$

⇒ $p^{2} + 2(p)(1) + 1^{2} - p^{2} = 17$

⇒ $p^{2} + 2p + 1 - p^{2} = 17$

⇒ $2p + 1 = 17$

⇒ $2p = 17 - 1$

⇒ $2p = 16$

⇒ $p = \frac {16}{2}$

⇒ $p = 8$

$\implies \textbf {Hence, the value of p is 8.}$

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