Question

P= 1! + 2x2! + 3x3!+.....+ 10x10!
find remaindere when (p+2) is divided
by
11!​

Answer 1

Answer:

Given P= 1! + 2x2! + 3x3! + 4x4! + ... + 10x10!

We have to find out the pattern of each term since each term is denoted in similar format (1*1!, 2*2! etc)

we can say, terms are in the format n*n!.

So, n*n! can be written as (n+1-1)*n!=(n+1)n!-n!=(n+1)!-n!

Now it is easy to find out P (Or sum of the factorial series given).

So, P=(2!-1!) + (3!-2!) + (4!-3!) + .................+ (11!-10!)=11!-1

So, P+2=11!-1+2=11!+1

So, the remainder when P+2 is divided by 11! is 1.

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Answer 2

Step-by-step explanation:

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