Question

(p+1)^3 expand using suitable identity ​

Answer 1

$\huge</p><p>\pink{\mid{\underline{\overline{\tt Answer : }}\mid}}$

Suitable Algebraic identity :

↪( a + b )³ = a³ + 3ab² + 3ab² + b³

Now ,

( p + 1 )³

= p³ + 3 × p² × 1 + 3 × p × 1² + 1³

= p³ + 3p² + 3p + 1

I hope it helps

Answer 2

$\huge\sf\underline{Solution}$We can solve this by using identity Identity

(a+b)³ = a³ + 3a²b + 3ab² + b³

So,

(p+1)³ = p³ +3p²(1)+3p(1)²+1

p³ + 3p²+3p+1 is the answer

So, (p + 1)³ = p³+3p²+3p+1

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Know more algebraic identities

(a+b)³ = a³+b³+3ab(a+b)

(a-b)³ = a³-b³-3ab(a-b)

(a + b + c )² = a²+b²+c²+2ab+2bc+2ca

a³ + b³ = (a+b)(a²-ab+b²)

a³ - b³ = (a-b)(a²+ab+b²)