P(-1,3), Q (1,2) find the magnitude of vector
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Step-by-step explanation:
Given,
OP
=1
i
^
+2
j
^
−3
k
^
and
OQ
=−1
i
^
−2
j
^
+1
k
^
,
where O is the origin.
Now,
PQ
=
OQ
−
OP
=(−1−1)
I
^
+(−2−2)
j
^
+(1−(−3))
k
^
=−2
i
^
−4
j
^
+4
k
^
∣
PQ
∣=
(−2)
2
+(−4)
2
+(4)
2
=6
Unit vector in the direction of
PQ
is,
PQ
^
=
∣
PQ∣
PQ
=
6
−2
i
^
−4
j
^
+4
k
^
=−
3
1
i
^
−
3
2
j
^
+
3
2
k
^
Hence direction cosines are (
3
−1
,
3
−2
,
3
2
)
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