(p-1) (p+2) (3p-1) find if these are in AP if it is find P
Answers
Answered by
2
Hey
Here is your answer,
A.P. : (p-1) , (p+2) , (3p-1)
Second term - first term = third term - second term
(p+2) - (p-1) = (3p-1) - (p+2)
p+2-p+1 = 3p-1-p-2
3 = 2p-3
2p = 3+3
2p = 6
p = 6/2
p = 3
Terms :
p-1 = 3-1
= 2
p+2 = 3+2
= 5
3p-1 = 3x 3-1
= 9-1
=8
Hope it helps you!
Here is your answer,
A.P. : (p-1) , (p+2) , (3p-1)
Second term - first term = third term - second term
(p+2) - (p-1) = (3p-1) - (p+2)
p+2-p+1 = 3p-1-p-2
3 = 2p-3
2p = 3+3
2p = 6
p = 6/2
p = 3
Terms :
p-1 = 3-1
= 2
p+2 = 3+2
= 5
3p-1 = 3x 3-1
= 9-1
=8
Hope it helps you!
Answered by
4
we have given that
p-1 ,p+3 ,3p-1 are in AP
we have to find P=?
solution :-
we know that :
if a,b,c are in AP
then 2b=a+c
Here,
=2 (p+3)=(p-1) +(3p -1)
=2p + 6=4p-2
=2p=8
=p =4 (ans)
HOPE IT HELP YOU
p-1 ,p+3 ,3p-1 are in AP
we have to find P=?
solution :-
we know that :
if a,b,c are in AP
then 2b=a+c
Here,
=2 (p+3)=(p-1) +(3p -1)
=2p + 6=4p-2
=2p=8
=p =4 (ans)
HOPE IT HELP YOU
Anonymous:
hihi, pata h ji;-)
pr apka kuch pata ny, sunday ko v jate ho kya pata ;-)
hehe!
kyue koi jata ha kya jo apko laga ma ve jati hu karka ji
ny jata to he koi, pr ese hi;-)
or ji kya chal raha h!
ma chal rahi hu ji aur kuch nii chal raha
sorry @sijasubbiah
but jasashmita or koi option ny h?!
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