Question

(p-1)(p-2)(p+3)(p+4)+6 factorize​

Answer 1

Answer:

given

(p-1 ) (p - 2 )(p +3) (p +4 )+6

now solve this

we get

( p² -2p -p +2 ) ( p²+ 4p + 3p + 12 ) +6

( p² -3p +2) ( p² +7p + 12 ) + 6

p4 +7 p³+12p²-3p³ -21p² -36p + 2p² + 14 p +24 +6

now solve this

we get

p4 +4p³ -7p² -22p + 30